done

Re: Tangent line problem from ****! lol :( help?

What have you tried? Here's a hint.

\(\displaystyle x^{2} + y^{2} = 1\)

To find dy/dx one must meddle with Implicit Differentiation.

\(\displaystyle 2x + 2y\cdot \frac{dy}{dx} = 0\)

Solving for dy/dx

\(\displaystyle \frac{dy}{dx} = -\frac{x}{y}\)

That will give one the slope of the tangent line at any desired point (excepting y = 0).

Now, you do it with your ellipse and see where it leads.
 
Re: Tangent line problem from ****! lol :( help?

So I used a point (1,2) and found a slope of -1/2

Knowing this equations slope is -1/2 (if im right) how do I prove that the original equation is = 1?
 
You also know the point is (1,2). Given a point and a slope, a unique line is determined.

Why did you pick a point? What happened to \(\displaystyle (x_{0},y_{0})\)?
 
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