1 - Log∣x+1∣
| x + 1|>0
For :
x+1>0
x > -1
2 - Log∣x−1∣∣x+1∣
D: ∣x−1∣∣x+1∣>0
|x+1|>0
x > -1
3 - Log∣x2−5x+4∣
|x^2 -5x +4 |>0 --- a+b+c=0 --- x'=1 , x''=4
Now would I look for the values where the values of x are positive (in the table of signs).
Is my work correct. Thanks for all the help .
| x + 1|>0
For :
x+1>0
x > -1
2 - Log∣x−1∣∣x+1∣
D: ∣x−1∣∣x+1∣>0
|x+1|>0
x > -1
3 - Log∣x2−5x+4∣
|x^2 -5x +4 |>0 --- a+b+c=0 --- x'=1 , x''=4
Now would I look for the values where the values of x are positive (in the table of signs).
Is my work correct. Thanks for all the help .