Domain of a function?

ProfessorFilostrato

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Jun 3, 2005
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10
Find the domain og y = the square root of x -2
Then use several values in the domain to make a table.

Ok...the domain is all X-values right?? So how do I find it???
 
Nope! sqrt(x-2) needs x>2. No negatives allowd under the radicle.
If you make the several values squares + 2 the table should be easy.
 
Alright...so the domain is all real numbers greater than or equal to 2? For my table I have under x: 2,3,4,5 under sqrt x - 2 I have 0, 1, 1.4, 1.8

Is that correct?
 
Personally, I'd prefer at least one more decimal place. Looks good, otherwise.
 
If you are satisfied with approximations they are correct up to 1.8. Since it is the shortened form of 1.732..., it would round to 1.7
I would have prefered
0, 1, sqrt(2), sqrt(3) which are exact. That's why I suggested squares+2 which avoids the question.
2, 3, 6, 11...
0, 1, 2, 3...
 
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