Can someone please help me answer this question? Find the domain and range of y=f(x)=6x^2+3
S scoopes81 New member Joined Nov 11, 2011 Messages 2 Nov 11, 2011 #1 Can someone please help me answer this question? Find the domain and range of y=f(x)=6x^2+3
S Shoppingal New member Joined Sep 28, 2011 Messages 28 Nov 12, 2011 #2 scoopes81 said: Can someone please help me answer this question? Find the domain and range of y=f(x)=6x^2+3 Click to expand... D = (xER) R = (yER,y<3) Hope this helps
scoopes81 said: Can someone please help me answer this question? Find the domain and range of y=f(x)=6x^2+3 Click to expand... D = (xER) R = (yER,y<3) Hope this helps
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,128 Nov 12, 2011 #3 Shoppingal said: D = (xER) R = (yER,y<3) Hope this helps Click to expand... If y = f(x) = 6x2 + 3, then the MINIMUM value of 6x2 occurs when x = 0. If x is NOT EQUAL to 0, then 6x2 > 0. So, if x = 0, f(x) = 0 + 3, or f(x) = 3. If x <0 or x > 0, 6x2 > 0, and f(x) > 0 + 3 f(x) > 3 Or, we can say that regardless of the value of x, f(x) > 3, and the range of the function should be all real numbers greater than or equal to 3.
Shoppingal said: D = (xER) R = (yER,y<3) Hope this helps Click to expand... If y = f(x) = 6x2 + 3, then the MINIMUM value of 6x2 occurs when x = 0. If x is NOT EQUAL to 0, then 6x2 > 0. So, if x = 0, f(x) = 0 + 3, or f(x) = 3. If x <0 or x > 0, 6x2 > 0, and f(x) > 0 + 3 f(x) > 3 Or, we can say that regardless of the value of x, f(x) > 3, and the range of the function should be all real numbers greater than or equal to 3.
