-sinAcscA- sin^2A- cos^2A-tanAcotA wut would it equal?? is it -3
I Iknownothing17 New member Joined Nov 1, 2007 Messages 6 Nov 30, 2007 #1 -sinAcscA- sin^2A- cos^2A-tanAcotA wut would it equal?? is it -3
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Nov 30, 2007 #2 Re: Trig identity Yes it would.
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Dec 1, 2007 #3 Hello, Iknownothing17! −sinAcscA−sin2A−cos2A−tanAcotA\displaystyle -\sin A\csc A - \sin^2A - \cos^2A - \tan A\cot A−sinAcscA−sin2A−cos2A−tanAcotA wut would it equal? .is it -3? . . . . Yes! Click to expand... We have: −sinA⋅1sinA⏟This is 1 − (sin2A+cos2A)⏟This is 1 − tanA⋅1tanA⏟This is 1 = − 1 − 1 − 1 = −3\displaystyle \text{We have: }\;-\underbrace{\sin A\cdot\frac{1}{\sin A}}_{\text{This is 1}} \; - \; \underbrace{(\sin^2A + \cos^2A)}_{\text{This is 1}} \;- \; \underbrace{\tan A\cdot\frac{1}{\tan A}}_{\text{This is 1}} \;\;=\;\; -\:1 \;- \;1 \;- \;1 \;\;=\;\;-3We have: −This is 1sinA⋅sinA1−This is 1(sin2A+cos2A)−This is 1tanA⋅tanA1=−1−1−1=−3
Hello, Iknownothing17! −sinAcscA−sin2A−cos2A−tanAcotA\displaystyle -\sin A\csc A - \sin^2A - \cos^2A - \tan A\cot A−sinAcscA−sin2A−cos2A−tanAcotA wut would it equal? .is it -3? . . . . Yes! Click to expand... We have: −sinA⋅1sinA⏟This is 1 − (sin2A+cos2A)⏟This is 1 − tanA⋅1tanA⏟This is 1 = − 1 − 1 − 1 = −3\displaystyle \text{We have: }\;-\underbrace{\sin A\cdot\frac{1}{\sin A}}_{\text{This is 1}} \; - \; \underbrace{(\sin^2A + \cos^2A)}_{\text{This is 1}} \;- \; \underbrace{\tan A\cdot\frac{1}{\tan A}}_{\text{This is 1}} \;\;=\;\; -\:1 \;- \;1 \;- \;1 \;\;=\;\;-3We have: −This is 1sinA⋅sinA1−This is 1(sin2A+cos2A)−This is 1tanA⋅tanA1=−1−1−1=−3
