okay, I think I understand that one now.
I am still confused about how the set of all polynomials of degree 2 fail to constitute a vector space. The vectors fail the following conditions:
Vector spaces must be closed under addition
Vector spaces must be closed under scalar multiplication
There must be a zero vector
I understand how they fail the addition closure: ( x^2+x+1 ) + (-x^2+x+1) = 2x + 2, which is not a degree 2 polynomial.
There is not a zero vector of degree 2.
But what about scalar multiplication?
Would a counter example be if
c = 0
then, c( x^2 + x + 1 ) = 0, which is not a vector of the polynomials of degree 2?