division of polynomials

[Guest]

This problem does not equal up to the answer

2
2x +4
________

2x

1x+2
2x/2x+4
2
2x +4

so in other word my answer is either 1x+2 or 1x+1 but neither one works becaus I still have the x

 

[stapel]

I'm sorry, but I can't make heads or tails of what you've posted, nor can I tell what you are supposed to be doing.

Please reply with clarification, including the full and exact statement of the exercise, the complete instructions, and a clear listing of what you have tried thus far. For formatting advice, please review the links in the "Forum Help" pull-down menu at the very top of the page. ("Karl's Notes" contains probably the quickest formatting to learn.)

Thank you.

Eliz.

 

[skeeter]

if you are attempting to divide (2x² + 4) by (2x), it's really not much of a division "problem" and does not require long division ...

\(\displaystyle \frac{2x^2+4}{2x}=\)

\(\displaystyle \frac{2x^2}{2x}+\frac{4}{2x}=\)

\(\displaystyle x + \frac{2}{x} = \frac{x^2+2}{x}\)

the final result is just dividing every term in the original fraction by 2.