Division of polynomials

burgerandcheese

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How do you prove that
1. the degree of the remainder < the degree of the divisor, and
2. the degree of the quotient is the difference between the degree of the polynomial and the degree of the divisor?

Is this all supposed to be intuitive?

TIA
 
Those are the conditions of division-operation.

The remainder - r(x) - must be of smaller degree than that of the divisor [q(x)]

If not - you will continue with division - and get a different remainder. That is what you do (in a way) during numerical division too!

Can you think of a counter-example?

The second condition is also true in a similar way. If you feel that it is not true - can you think of a counter-example?
 
In one sense, this is a definition, not a theorem that needs a proof. We define the remainder as having a degree less than the divisor.

What needs proof is the existence and uniqueness of the whole thing -- that for any polynomials a and b, polynomials q and r satisfying the definition exist, and there are only one of each. You can find proofs all over the place, for example here and here. But in a sense, the proof is seen whenever you carry out such a division -- the fact that there is a way to do it tells you that it can be done (and, in particular, that you can get the degree of the remainder to be less than that of the divisor).

The statement about the degrees of q, a, and b is implied by the definition, since when you multiply b and q, the degree of the product, a, is the sum of the degrees of b and q.
 
Those are the conditions of division-operation.

The remainder - r(x) - must be of smaller degree than that of the divisor [q(x)]

If not - you will continue with division - and get a different remainder. That is what you do (in a way) during numerical division too!

Can you think of a counter-example?

The second condition is also true in a similar way. If you feel that it is not true - can you think of a counter-example?

I can't think of a counter-example for either conditions
 
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