Division of a ploynomial

[silverdragon316]

I worked this problem out but I seem not to bring things down in the right order.
the problem is:
(3x^4-x^3+2x^2-5) / (x^2-3)

I set it up and divide the problem by (x^2-3). I put +0x for the missing term in the problem and start dividing. I came up with 3x^2-x+11 R.-3x+28 over x^2-3

Would this be the right answer. If not, then I guess I am not bring things down in the right order. :?

 

[arthur ohlsten]

3x^2 -x +11
____________________
x^2-3 l 3x^4-x^3+2x^2+0x-5
3x^4 -9x^2
---------------------------
-x^3 +11x^2+0x-5
-x^3 +3x
-----------------------------
11x^2 -3x-5
11x^2 -33
-------------------
- 3x +28 remainder

your answer is right
you can prove it by multiplying [x^2-3][3x^2-x+11] and adding -3x+28

Arthur