Division but complicated

[qw1478]

Hey guys I tried for 10 minutes, not able to solve this.

(1/x+1/x+1) / (1/x-1/x+1)

1/x+1 - x/x-1 = -2x/x^2-1

Please give me the right directions guys. Thanks a lot.

 

[Deleted member 4993]

Hey guys I tried for 10 minutes, not able to solve this.

(1/x+1/x+1) / (1/x-1/x+1)

1/x+1 - x/x-1 = -2x/x^2-1

Please give me the right directions guys. Thanks a lot.

Try to simplify the numerator and the denominator separately. Then put those together.

Please show us your work, indicating exactly where you are stuck - so that we know where to begin to help you.

 

[Loren]

Hey guys I tried for 10 minutes, not able to solve this.

(1/x+1/x+1) / (1/x-1/x+1)<<< This says \(\displaystyle \frac{\frac{1}{x}+\frac{1}{x}+1}{\frac{1}{x}-\frac{1}{x}+1}\). Please show where you are in the problem.

1/x+1 - x/x-1 = -2x/x^2-1 <<<This says \(\displaystyle \frac{1}{x}+1-\frac{x}{x}-1 = \frac{-2x}{x^2}-1\). Ditto. However, a good rule to follow is to multiply both sides of the equation by least common denominator of all the fractions.

Please give me the right directions guys. Thanks a lot.

 

[mmm4444bot]

(1/x+1/x+1) / (1/x-1/x+1) What is this typing supposed to mean?

Here's what it actually means (following the order of operations).

\(\displaystyle \frac{\frac{1}{x} \;+\; \frac{1}{x} \;+\; 1}{\frac{1}{x} \;-\; \frac{1}{x} \;+\; 1}\)

I could guess that your typing is supposed to mean something else. The following is only one possible guess.

\(\displaystyle \frac{\frac{\frac{1}{x \;+\; 1}}{x \;+\; 1}}{\frac{\frac{1}{x \;-\; 1}}{x \;+\; 1}}\)

Is this guess correct? :?

If so, then we type it as follows.

([1/(x + 1)]/[x + 1])/([1/(x - 1)]/[x + 1])

THIS SITE explains how to properly type mathematical expressions.

Also, do you know that dividing by a ratio is the same as multiplying by its reciprocal? (I see a major cancellation pending, if my guess above is correct.)