n5-18n4=3n3 divided by n3 Please help, ASAP! :!: [/code]
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 May 30, 2005 #2 bud said: n5-18n4=3n3 divided by n3 Please help, ASAP! :!: Click to expand... First, before dividing, let's recall that n != 0 -- 'n' cannot be zero. Have you learned rules of exponents? a^m / a^r = a^(m-r) That's about it. n^5 - 18n^4 = 3n^3 divided by n^3 n^5/n^3 - 18n^4/n^3 = 3n^3/n^3 n^(5-3) - 18n^(4-3) = 3n^(3-3) n^2 - 18n^1 = 3n^0 n^2 - 18n = 3(1) n^2 - 18n = 3 Now what?
bud said: n5-18n4=3n3 divided by n3 Please help, ASAP! :!: Click to expand... First, before dividing, let's recall that n != 0 -- 'n' cannot be zero. Have you learned rules of exponents? a^m / a^r = a^(m-r) That's about it. n^5 - 18n^4 = 3n^3 divided by n^3 n^5/n^3 - 18n^4/n^3 = 3n^3/n^3 n^(5-3) - 18n^(4-3) = 3n^(3-3) n^2 - 18n^1 = 3n^0 n^2 - 18n = 3(1) n^2 - 18n = 3 Now what?
A arthur ohlsten Full Member Joined Feb 20, 2005 Messages 852 May 31, 2005 #3 n^5-18n^4-3n^3 divided by n^3 divide as in 6th grade math n^2 -18n -3 ----------------------- n^3 l n^5-18n^4-3n^3 n^5 --------------- -18n^4 -18n^4 ---------------- -3n^3 -3n^3 -------------- 0 remainder Arthur
n^5-18n^4-3n^3 divided by n^3 divide as in 6th grade math n^2 -18n -3 ----------------------- n^3 l n^5-18n^4-3n^3 n^5 --------------- -18n^4 -18n^4 ---------------- -3n^3 -3n^3 -------------- 0 remainder Arthur