Dividing Polynomials: (x^5 + 1)/(x^3 +1) = x^2 remainder -x^2 + 1

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BigNate

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Oct 2, 2016
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Hello Everyone,

I'm sure I have learned this at some point in the past, but I seem to have forgot the methodology.

I understand that (x^5 + 1)/(x^3 +1) = x^2 remainder -x^2 + 1. Can someone please explain this to me? I thought the remainder would only be -x^2, but apparently I am incorrect.

Thank you in advance for your time!
 
BigNate said:
I'm sure I have learned this at some point in the past, but I seem to have forgot the methodology.

I understand that (x^5 + 1)/(x^3 +1) = x^2 remainder -x^2 + 1. Can someone please explain this to me?
Click to expand...
What do you mean by "understanding" the division, while needing an explanation of how the division works?

BigNate said:
I thought the remainder would only be -x^2, but apparently I am incorrect.
Click to expand...
What were your steps in the long polynomial division (here) which led to your answer?

Please be complete. Thank you! ;)
 
I meant "I've been told" not "I understand". I definitely did not understand.

The link you provided is exactly what I need though. I know it is something I did about 15 years ago, but I couldn't find the right refresher. You provided me with a good source though...thank you!
 
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