dividing polynomials: how to do (24x2-19x+6)/(8x-1)

[2xblessed]

hi, i was wondering if anybody could tell me how to develop the answer for this polynomial problem:

(24x2-19x+6)/(8x-1)

Thank you

 

[Loren]

Re: dividing polynomials

Long division seems to be the best alternative.

 

[Denis]

Re: dividing polynomials

(24x2-19x+6)/(8x-1)

Next time, write "squared" as ^2; like 24x^2

Are you sure you posted that correctly? I think your -19x should be -17x

 

[Deleted member 4993]

Re: dividing polynomials

Are you sure you posted that correctly? I think your -19x should be -17x

Would that make this problem any simpler - I think not.

However, if the constant term changed from "+6" to "+2" - that could be considered simpler.

 

[Denis]

Yikes; forgot to triple my 17x: 19x should be 51x ; 1st mistake this year

(24x^2 - 51x + 6) / (8x - 1) ; x = 2 or 1/8

 

[soroban]

Hello, 2xblessed!

i was wondering if anybody could tell me how to answer this polynomial problem:

. . $\displaystyle (24x^2-19x+6) \div (8x-1)$

How about long division?

. . $\displaystyle \begin{array}{cccccc}& & & 3x & -2 \\ & & -- & -- & -- \\ 8x-1 & ) & 24x^2 & -19x & +6 \\ & & 24x^2 & - 3x \\ & & -- & -- \\ & & & -16x & +6 \\ & & & -16x & +2 \\ & & & -- & -- \\ & & & & +4 \end{array}$


$\displaystyle \text{Therefore: }\;(24x^2 - 19x + 6) \div (8x - 1) \;\;=\;\;3x-2 + \frac{4}{8x-1}$