Dividing polynomials: 32a^3+24a/8a, 4x^3+x+3/2x-1

[zhyia]

32a^3+24a/8a

=4a^2+3


4x^3+x+3/2x-1

Im not sure how to begin working this problem?

2x-1/4x^3+x+3 maybe divide like terms?

 

[steve_b]

32a^3+24a/8a =4a^2+3

I'm sure you meant (you need parentheses in the numerator to indicate that the 8a divides both terms in the numerator):

(32a^3 + 24a) / (8a)

which gives:

4a^2 + 3

4x^3+x+3/2x-1

Im not sure how to begin working this problem?

2x-1/4x^3+x+3 maybe divide like terms?

Again, you need some parentheses. If you mean:

(4x^3 + x + 3) / (2x - 1)

then you're out of luck. This can't be easily simplified without polynomial long division, which gives a remainder. Have you covered that material? Did you make a error typing the problem?

Steve

 

[zhyia]

No its typed correctly and your right the final answer will end up with a remainder...I know exactly what to do...it has to be solved using long division

 

[steve_b]

OK. Then I get:

2x^2 + x with a remainder of 2x + 3

Steve