Dividing Polynomial: (6 - 7x - 3x^2) by (2 - x)

[Guest]

Hi. My homework equation says to divide (6 - 7x - 3x^2) by (2 - x)


So I set it up as

****-3x + 13 - 32 / (2 - x)
-x - 2 ) 3x^2 - 7x + 6
*******3x^2 - 6x
******------------
************13x + 6
************13x -26
************---------
****************32

(the stars are there just to keep it in line.)

I got, as an answer -3x + 13 - 32 / (2 - x)

I went wrong when I divided somewhere because my answer isn't even an option, but I'm pretty sure I'm close. Can someone help me out and point out where I went wrong?

 

[brendan3eb]

First, multiply the problem by -1/-1 so that you can do synthetic division.

2 | 3 7 -6
**|*6**26
**---------
**3 13 -20

thus your answer is 3x + 13 with a remainder of -20

 

[galactus]

You are merely having sign troubles. Common in polynomial long division.

       3x+13
      ------------------------------------
-x+2 |-3x^2-7x+6
      -3x^2+6x
       -------------------------
            -13x+6
            -13x+26
                -----------------------
                          -20

Answer: \(\displaystyle 3x+13+\frac{20}{x-2}\)

Getting this to line up is a booger, huh?.

 

[Guest]

Thanks so much. That helps tons!!!!

I put in the wrong signs on accident when I posted it on this forum, but just from your explanations on how to solve it, I was able to figure out the answer.

Thanks a ton!