dividing logs

[jjazz21]

Please help divide this log and find X: \(\displaystyle \displaystyle x=\frac{log_{9}(32)}{log_{9}(2)}\)

 

[galactus]

Rewrite the numerator using log properties, \(\displaystyle log_{9}(32)=5log_{9}(2)\)

 

[jjazz21]

Rewrite the numerator using log properties, \(\displaystyle log_{9}(32)=5log_{9}(2)\)

do u know what x=

 

[Mrspi]

do u know what x=

Yes, I do.

And if you follow the suggestion made by galactus, you should be able to figure it out, too!

32 = 2⁵

log₉ 32 = log₉ 2⁵

And there's a rule for logs which says log_b aⁿ = n*log_b a

Ok....now, you should be able to finish it....

If you are still having trouble, please show us what you've done, so we can see where you need further help.