Dividing and adding fractions with 2 variables

daffy88

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Aug 16, 2009
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I cannot guarantee that this is "intermediate" algebra, but I think of myself as more or less knowledgable of basic algebra, and I cannot figure this out for the life of me:

2 / 2/x + 2/y

When I do the problem, I come out with xy/2, which I know is incorrect because, first of all, that is not an answer choice, and second of all, I peeked at the answer and it is xy/x+y. I do not understand how to get to the correct answer. My work to get xy/2:

2 / 2/x + 2/y =
2 * x/2 + y/2 =
2/1(x/2 + y/2) =
2x/2 + 2y/2 =
2x + 2y/4 =
xy/2

Any help available to explain what I am doing wrong or not doing? Thanks!
 
daffy88 said:
I cannot guarantee that this is "intermediate" algebra, but I think of myself as more or less knowledgable of basic algebra, and I cannot figure this out for the life of me:

2 / 2/x + 2/y <<< Not clear as to what this means. You need to use parenthesis to clarify.

When I do the problem, I come out with xy/2, which I know is incorrect because, first of all, that is not an answer choice, and second of all, I peeked at the answer and it is xy/x+y. I do not understand how to get to the correct answer. My work to get xy/2:

2 / 2/x + 2/y = ??? 22x+2y\displaystyle \frac{2}{\frac{2}{x}}+\frac{2}{y}
2 * x/2 + y/2 = ??? 2x2+y2\displaystyle 2\cdot \frac{x}{2}+\frac{y}{2}
2/1(x/2 + y/2) =
2x/2 + 2y/2 =
2x + 2y/4 =
xy/2

2x2+y2=\displaystyle 2\cdot \frac{x}{2}+\frac{y}{2}=

x+2y=\displaystyle x+\frac{2}{y}=

xyy+2y\displaystyle \frac{xy}{y}+\frac{2}{y}

xy+2y\displaystyle \frac{xy+2}{y}

Any help available to explain what I am doing wrong or not doing? Thanks!
 
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