Divide (6x^3 - 7x^2 - 34x + 15) by (x - 3)

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Stine

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(6x^3-7x^2-34x+15) by (x-3)


_____6x^2-34x+15
x-3/6x^3-7x^2-34x+15
-(6x^3+6x^2)
__________________
x^2-34x
- x^2-34x
_______________
0+15

Karl's notes sais there was no easy way to type a division problem out but I trid to show my steps if this is understandable??? :wink: If someone can help me please. Thank you
 
I think you mean that you are supposed to divide 6x^3 - 7x^2 - 34x + 15 by x - 3, and that you are supposed to use long division. And I think you mean your work to be as follows:

Code: 
       6x^2 -   34x +  15
      ------------------------
x - 3 )6x^3 -  7x^2 - 34x + 15
       6x^3 - 18x^2
       -----------------------
              11x^2 - 34x + 15
              ...
Is the above correct? (I'm afraid I don't follow your steps entirely, which is why I didn't show all of it. For instance, how did 6x<sup>2</sup>(x - 3) become 6x<sup>3</sup> - 6x<sup>2</sup>?)

Thank you.

Eliz.
 
That is what I was tryign to type out. I 6x^3 became 6x^2 when I divided x into 6x^3 and x^3 became x^2 when I subtracted them from eachother. I thought that was part of the steps.

Thank you and I appreciate your time.
 
synthetic division ...

Code: 
3] ... 6 ... -7 ... -34 ... 15

............ 18......33 ... -3
------------------------------
.......6.....11......-1 ... 12

quotient is \(\displaystyle \L 6x^2 + 11x - 1 + \frac{12}{x-3}\)
 
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