Distributive Law

[mathxyz]

3(x) times 3(x + 1) times 3(2 - x) =

My answer: -27x^3 + 27x^2 + 54

Am I right?

 

[Denis]

3(x) times 3(x + 1) times 3(2 - x) =
My answer: -27x^3 + 27x^2 + 54
Am I right?

No.

 

[Matt]

3(x) times 3(x + 1) times 3(2 - x) =

My answer: -27x^3 + 27x^2 + 54

Am I right?

No, but you are close; the correct answer is -27x³ + 27x² + 54x.

 

[mathxyz]

Yes..

Yes, I forgot to include the variable x with 54. I was not off by much.

 

[Denis]

Re: Yes..

Yes, I forgot to include the variable x with 54. I was not off by much.

Yes Sir; you were most certainly not off by much.
Perhaps the Honorable Guido will give you 100%.

 

[~Midnight.Kitten~]

3(x) times 3(x + 1) times 3(2 - x) =

My answer: -27x^3 + 27x^2 + 54

Am I right?

No, but you are close; the correct answer is -27x³ + 27x² + 54x.

if you were asked to combine them into like terms, would it be possible with the ^3 and ^2

 

[tkhunny]

Cubes and squares are NOT "like" terms.

It must match on all bases and exponents.

x^3 and y^3 No. Same exponent but different bases
x^2 and x^3 No. Same base but different exponents
x*y and x^2 No. Same TOTAL exponent, but not anything else.
x^2*y and x*y^2 No. Same TOTAL exponent, but not anything else.

 

[Denis]

-27x^3 + 27x^2 + 54x

All you can do with that, Black Cat, is simplify it a bit:
-27x(x^2 - x - 2)

 

[arthur ohlsten]

or simplify it to :
-3^3 x (x+1) (x-2)
Arthur

 

[mathxyz]

hey

Great notes for my math files.