Mathemagician
New member
- Joined
- Jun 3, 2014
- Messages
- 1
Find all points with a distance of 5 units away from the plane defined by the equation 2x - 3y + 4z + 5 = 0.
My solution was to use: |Ax + By + Cz + D| / sqrt(A^2 + B^2 + C^2) = 5. The result I got were:
|2x - 3y + 4z + 5| = 5sqrt(29).
Answer 1: 2x - 3y + 4z + 5 = 5sqrt(29).
Answer 2: -2x + 3y - 4z - 5 = 5sqrt(29).
Are these correct? If not, how would one go about solving this question?
My solution was to use: |Ax + By + Cz + D| / sqrt(A^2 + B^2 + C^2) = 5. The result I got were:
|2x - 3y + 4z + 5| = 5sqrt(29).
Answer 1: 2x - 3y + 4z + 5 = 5sqrt(29).
Answer 2: -2x + 3y - 4z - 5 = 5sqrt(29).
Are these correct? If not, how would one go about solving this question?