I'm not sure if this is a shared labor problem or not. No matter how I set it up, it doesn't work out.
Please reply showing your set-up.
Janet jogged 10 miles then cycled 45.5 miles. She finished both in a total of 4.5 hours. She cycled 6 mph faster than she jogged. What was her rate when cycling?
To learn the general process for setting up this sort of exercise, please try (
here). Using the method explained there:
. . .jogging:
. . . . .rate: r
. . . . .time: t
. . . . .distance: 10 = rt
. . .cycling:
. . . . .rate: [
create expression, in terms of "r", for this rate]
. . . . .time: [create expression, in terms of "t", for the amount of the 4.5 hours left after she'd jogged]
. . . . .distance: 45.5
Solve the first equation for one of the variables in terms of the other; say, solve for t = 10/r. Then plug this into the second equation, and solve for the variable. If you use "t = 10/r", then you'll be solving for the value of r. At some point, you may find it useful to multiply through on both sides by "r", in order to get the variable out of the denominator (and also, if you prefer, by 2, in order to get rid of the decimals; and then divide by 3, to make the coefficients smaller).
Apply the Quadratic Formula (
here) to the result. Remember that only one of those solutions will make sense within the context of somebody travelling
forward.
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