Discussing Exponent Rules

[Gouskin]

For appropriate a, b, and c:

$\displaystyle (a \cdot b)^c = a^cb^c$

$\displaystyle \dfrac{a^b}{a^c} = a^{b - c}$

$\displaystyle a^0 = 1, \ \ a \ne 0 \ \ and$

$\displaystyle 0^a = 0, \ \ a > 0$

are some other exponent rules.

You just restated the same rules, though.

 

[lookagain]

You just restated the same rules, though.

Gouskin, I (allegedly) "just restated" what "same rules?" Refer to what you mean by the post number in this thread. For one instance, $\displaystyle \ (a \cdot b)^c = a^cb^c \$ you claim is a restatement of what rule?

 

[Gouskin]

Gouskin, I (allegedly) "just restated" what "same rules?" Refer to what you mean by the post number in this thread. For one instance, $\displaystyle \ (a \cdot b)^c = a^cb^c \$ you claim is a restatement of what rule?

is a restatement of

because
x/y = x*y^(-1)

is the same as

because

.
This could only be true if they follow the rules of multiplicity.
And if they follow this rule, the exponent MUST be distributed throughout a multiplication of terms enclosed in parentheses.