Discontinuity of (x^2 - 2x - 8)/(x + 2) at a = -2

[scrum]

For the function below to have a removeable discontinuity at "a", state the value of g(a), where g(x) agrees with f(x) for all x not equal to "a".

. . . . .f(x) = (x² - 2x - 8) / (x + 2), with a = -2

There are a list of other problems below but they are all the same concept.

The first thing I did was factored the top and got

(x-4)(x+2) / (x+2)

which cancels to (x-4) / 1

Then I plugged in -2 as x and got 2/1 or 2, howevver 2 is the wrong answer.

I think i'm confusted about what the problem is acually asking me to do. Can someone point out the error of my ways?
_________________________
Edited by stapel -- Reason for edit: Replacing graphic with text.

 

[pka]

But if x=-2 then x-4=-6!

 

[scrum]

*blinks*

wow. I hate when that happens.
Thanks.