eq 1) LxW=12
eq 2) 2L+2W=14
eq 2) L+W=7 or W=7-L.....substitute into eq 1)
Lx[7-L]=12
7L -L^2=12
L^2-7L+12=0 factor
factors of 12 are 1,12...2,6...3,4
we want a set whose sum =7 3,4 does it
[L-3][L-4]=0
L=3 or L=4 substitute into eq 1
L=3 then W=4
L=4 then W=3 answer
Arthur
