Difficult Math

Cherrybear

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Nov 12, 2020
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Hi, I have an equation I need to solve. I need to figure out 3^2019÷5 because I need to know the remainder.
I already solved 3^2000÷5, and the remainder is 1, and 3^19, which has a remainder of 2.
All I need to know is how to put these together, and I know 3^2019=3^2000x3^19, but how exactly would I find the remainder from the two I have? If possible?
Thanks!
 
Hi, I have an equation I need to solve. I need to figure out 3^2019÷5 because I need to know the remainder.
I already solved 3^2000÷5, and the remainder is 1, and 3^19, which has a remainder of 2.
All I need to know is how to put these together, and I know 3^2019=3^2000x3^19, but how exactly would I find the remainder from the two I have? If possible? Thanks!
I observe that the remainder comes in groups of (4, 2, 1, 3). What can you do with that information?
 
Hi, I have an equation I need to solve. I need to figure out 3^2019÷5 because I need to know the remainder. I already solved 3^2000÷5, and the remainder is 1, and 3^19, which has a remainder of 2. All I need to know is how to put these together, and I know 3^2019=3^2000x3^19, but how exactly would I find the remainder from the two I have? If possible?
See here
 
Hi, I have an equation I need to solve. I need to figure out 3^2019÷5 because I need to know the remainder.
I already solved 3^2000÷5, and the remainder is 1, and 3^19, which has a remainder of 2.
All I need to know is how to put these together, and I know 3^2019=3^2000x3^19, but how exactly would I find the remainder from the two I have? If possible?
Thanks!
You know these facts:

3^2000 has remainder 1, so that 3^2000 = 5m + 1​
3^19 has remainder 2, so that 3^19 = 5n + 2​

So 3^2019 = 3^2000 * 3^19 = (5m + 1)(5n + 2) = ...

What does that tell you about the remainder? (And what does it suggest about a general rule worth knowing?)
 
Thanks everyone, you all helped a lot- I found that the remainder was 2, simply by multiplying the two numbers! (I don't know why I didn't think of that before XD)
 
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