Differentiation???

[steve_254]

someone wanna guide me through

f(x) = [ 3x^(2/5) - sqr(x) ] / x^2


and work out:

f(x) = 3pi^2cosx + sinx

i have an answer for that one i just wanna check if it is correct or not
thanks in advance

 

[stapel]

Post your answer, and we'll be glad to check it.

Thank you.

Eliz.

 

[steve_254]

for f(x) = 3pi^2cosx + sinx

i got 3pi^2(-sinx + cosx)

 

[stapel]

Why did the 3(pi)² go from being multiplied on only the first term to being multiplied on both? That is to say, how did you get the derivative of sin(x) as being 3(pi)²cos(x)?

Eliz.

 

[Guest]

f(x) = 3pi^2cosx + sinx

f'(x) = (-3pi^2)sinx + cosx