Differentiation when x=-1

IloveManUtd

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Jul 27, 2010
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Given that y= (2x+3)[sup:1rlan0cz]5[/sup:1rlan0cz](x+2)[sup:1rlan0cz]8[/sup:1rlan0cz], find the value of dy/dx when x=-1?

I'm confused with this question: where and when do I put -1 in?
 
y = f(x) = (2x+3)5(x+2)8\displaystyle y \ = \ f(x) \ = \ (2x+3)^5(x+2)^8

f(x) = ?\displaystyle f'(x) \ = \ ?

f(1) = ?\displaystyle f'(-1) \ = \ ?
 
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