Differentiation when x=-1

IloveManUtd

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Jul 27, 2010
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Given that y= (2x+3)[sup:1rlan0cz]5[/sup:1rlan0cz](x+2)[sup:1rlan0cz]8[/sup:1rlan0cz], find the value of dy/dx when x=-1?

I'm confused with this question: where and when do I put -1 in?
 
\(\displaystyle y \ = \ f(x) \ = \ (2x+3)^5(x+2)^8\)

\(\displaystyle f'(x) \ = \ ?\)

\(\displaystyle f'(-1) \ = \ ?\)
 
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