A cone of radius r and height h has volume 81pi.
a) Show that the curved surface area of the cone is given by S= pi x sqrt r4 + 2432/r2
My working:
Volume = 1/3 x pi x r2x h
81pi = 1/3 x pi x r2x h
243/r2= h
Surface Area = pi x r x l
l2 = h2 + r2
l^2 = (243/r^2)^2 + r^2
l^2 = 59049/r^4 +r^2
l^2 = 59094/r^4 +r^6/r^4
l^2 = 59094 + r^6/ r^4
l = sqrt all the above
l = sqrt59094 + r^6/ r^2
S = pi x r x l
= pi x r x sqrt59094 + r^6/ r^2
= pi x sqrt 59094 + r^6/ r
No idea how to get to the answer they want after this point.
a) Show that the curved surface area of the cone is given by S= pi x sqrt r4 + 2432/r2
My working:
Volume = 1/3 x pi x r2x h
81pi = 1/3 x pi x r2x h
243/r2= h
Surface Area = pi x r x l
l2 = h2 + r2
l^2 = (243/r^2)^2 + r^2
l^2 = 59049/r^4 +r^2
l^2 = 59094/r^4 +r^6/r^4
l^2 = 59094 + r^6/ r^4
l = sqrt all the above
l = sqrt59094 + r^6/ r^2
S = pi x r x l
= pi x r x sqrt59094 + r^6/ r^2
= pi x sqrt 59094 + r^6/ r
No idea how to get to the answer they want after this point.