differentiate

[ocgirl83]

differentiate implicitly to find dy/dx. Then find the slope of the curve at the given point: 4x^3-y^4-3y+5x+1=0; (1, -2).

 

[jsbeckton]

do you just want someone to do it for you?

 

[jsbeckton]

i got -7/29, better check my arithmitic, did it quickly. What did you get?

 

[ocgirl83]

ive finished it i just want to know what someone else got for it

 

[ocgirl83]

17/29 as slope and 12x^2+5/-4y^3-3 as the differentiate of dy/dx

 

[jsbeckton]

sorry, typo, I meant -17/29

I had the same but had -5-12x^2 in the numerator

 

[stapel]

ive finished it i just want to know what someone else got for it...17/29 as slope and 12x^2+5/-4y^3-3 as the differentiate ["derivative"?] of dy/dx

I get different signs in the denominator. And I agree with jsbeckton on the value of the derivative at (x, y) = (1, -2).

Please reply showing your steps, and we'll be glad to help you correct any errors.

Thank you!

Eliz.