Differentiate the function f(x) = ?30 h(x) = (x - 2)(2x+3) y = 5e^x + 3
B bballj228 New member Joined Jun 17, 2008 Messages 9 Jun 30, 2008 #1 Differentiate the function f(x) = ?30 h(x) = (x - 2)(2x+3) y = 5e^x + 3
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Jun 30, 2008 #2 Re: differentiate Review the basic rules for derivatives.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Jul 2, 2008 #3 These are very basic: f(x)=30\displaystyle f(x) = \sqrt{30}f(x)=30 Click to expand... This is a constant. What is the derivative of a constant always equal?. h(x)=(x−2)(2x+3)\displaystyle h(x) = (x - 2)(2x+3)h(x)=(x−2)(2x+3) Click to expand... Either expand and differentiate term by term or use the product rule. y=5ex+3\displaystyle y = 5e^{x} + 3y=5ex+3 Click to expand... Again, what is the derivative of 3, a constant?. The derivative of ex=ex\displaystyle e^{x}=e^{x}ex=ex
These are very basic: f(x)=30\displaystyle f(x) = \sqrt{30}f(x)=30 Click to expand... This is a constant. What is the derivative of a constant always equal?. h(x)=(x−2)(2x+3)\displaystyle h(x) = (x - 2)(2x+3)h(x)=(x−2)(2x+3) Click to expand... Either expand and differentiate term by term or use the product rule. y=5ex+3\displaystyle y = 5e^{x} + 3y=5ex+3 Click to expand... Again, what is the derivative of 3, a constant?. The derivative of ex=ex\displaystyle e^{x}=e^{x}ex=ex
