Differentiate capacitor discharge formula

[Tye]

Any help would be appreciated as my tutor is I'll and colleges shut down

I got dv/dt = v/t X ( 1+e^-t/T)

But I think it's wrong and not 100% I fully understand it

 

[Steven G]

What is the derivative of -t/T wrt t

 

[Tye]

What is the derivative of -t/T wrt t

I don't know not understanding calculus I'm sorry really struggling I have had no tutoring just having to learn from YouTube videos ( thanks to covid 19)
I was asked to to differentiate the capacitor discharging formula
With t = 2.2
And T = 2.2
And circuit voltage 5 volts

 

[Tye]

This was the question and answer example for charging I understand the first b

 

[Tye]

This was the question and answer example for charging I understand the first b

Could you explain how they differentiated this equation this was the example if I can understand that then maybe I can do discharge equation

 

[Steven G]

[math]\dfrac{d}{dt}(e^{kt}) = ke^{kt} \ and \ \dfrac{d}{dt}({kt}) = k[/math]

 

[Tye]

[math]\dfrac{d}{dt}(e^{kt}) = ke^{kt} \ and \ \dfrac{d}{dt}({kt}) = k[/math][/QUOT
Evaluate the rate of change for the following formula ( discharge of a capacitor )
Q = Ve^-t/T
V = 5
t = 2.2
T ( time constant) = 2.2
What would you get for that please big help, I am going round in circles really want to understand it

 

[Tye]

My understanding is t is the veruble
And rest are constants