Differential equation

There is a standard "reduction of order" method. I suspect that this problem was designed to test that! Since you are told that 1t+12\displaystyle \frac{1}{t}+\frac{1}{2} is a solution to this differential equation, try a solution of the form u(t)(1t+12)=u(t)t+u(t)2\displaystyle u(t)\left(\frac{1}{t}+ \frac{1}{2}\right)= \frac{u(t)}{t}+ \frac{u(t)}{2} and try to determine u.
 
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