Differential Equation with Matrices. Undetermined Coefficients?

ChrisGuy

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Apr 18, 2020
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Hi, I am hoping someone could lead with this problem, I think I have to use the method of undetermined coefficients, but I am not entirely sure since the work gets incredibly overwhelming and messy. I solved for the eigenvectors and found a predicted solution (as you should for undetermined coefficients), but taking the derivative of it is a huge mess, so I think I must be missing something. Math.PNG
 
Hi, I am hoping someone could lead with this problem, I think I have to use the method of undetermined coefficients, but I am not entirely sure since the work gets incredibly overwhelming and messy. I solved for the eigenvectors and found a predicted solution (as you should for undetermined coefficients), but taking the derivative of it is a huge mess, so I think I must be missing something. View attachment 18000
Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520

Please share your work/thoughts about this assignment
 
Hi, I am hoping someone could lead with this problem, I think I have to use the method of undetermined coefficients, but I am not entirely sure since the work gets incredibly overwhelming and messy. I solved for the eigenvectors and found a predicted solution (as you should for undetermined coefficients), but taking the derivative of it is a huge mess, so I think I must be missing something. View attachment 18000
Here's a potential starting point. Ideally what we would like to do is to just let [math]u = \left ( \begin{matrix} x(t) \\ y(t) \\ z(t) \end{matrix} \right )[/math] and multiply it out to get three uncoupled equations, but the way it stands the matrix A is going to mix the functions x(t), y(t), z(t) in each of the three equations: like [math]\dfrac{du}{dx} = ax(t) + by(t) + cz(t) + \text{ exponential terms.}[/math] So we need to diagonalize A (aka change the basis) so that when we set [math]u = \left ( \begin{matrix} x(t) \\ y(t) \\ z(t) \end{matrix} \right )[/math] we get three equations in x(t), y(t), and z(t) that aren't mixed together and then you can do undetermined coefficients with each equation. (Or all at once if you prefer to keep working with the matrices.)

See what you can do with that.

-Dan
 
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