Differential Equation question
- Thread starter lilshai
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Maybe they noticed the pattern in the two terms. Try differentiating f(x) = e<sup>-5x</sup>. What do you get?
So if you have ye<sup>-5x</sup> = 0, what will you get if you differentiate implicitly with respect to x?
Eliz.
P.S. I'm not saying that this is "the" way to do it, but, until somebody comes along with a proper methodology, this at least gives you a hint of a possibly-useful way to look at things.
So if you have ye<sup>-5x</sup> = 0, what will you get if you differentiate implicitly with respect to x?
Eliz.
P.S. I'm not saying that this is "the" way to do it, but, until somebody comes along with a proper methodology, this at least gives you a hint of a possibly-useful way to look at things.
Hello,
I noticed that if I differentiate ye^((-5x)=0 I get exactly the step before it, e^((-5x))*y' - 5e^((-5x))*y = 0 using the product rule and implicit differentiation, so that makes sense. but how would you know how to go the other way around? Is there a method or do you just look for patterns?
I noticed that if I differentiate ye^((-5x)=0 I get exactly the step before it, e^((-5x))*y' - 5e^((-5x))*y = 0 using the product rule and implicit differentiation, so that makes sense. but how would you know how to go the other way around? Is there a method or do you just look for patterns?