I just can't get this problem...
dy/dt = te^y with the initial condition y(1) = 0
I got
e^-y dy = x dx
The after integration
-e^-y = (x^2 / 2) + C
y= ln ( x^2 / 2 + C )
0 = ln( 1 / 2 + C)
Thats where i get stuck I don't know quite how to solve for C.
Thats if i did all the previous steps correct. Any Help is Appreciated!
dy/dt = te^y with the initial condition y(1) = 0
I got
e^-y dy = x dx
The after integration
-e^-y = (x^2 / 2) + C
y= ln ( x^2 / 2 + C )
0 = ln( 1 / 2 + C)
Thats where i get stuck I don't know quite how to solve for C.
Thats if i did all the previous steps correct. Any Help is Appreciated!