Differential Equation help!

Gamer3o3

New member
Joined
Mar 10, 2012
Messages
2
I just can't get this problem...
dy/dt = te^y with the initial condition y(1) = 0

I got
e^-y dy = x dx
The after integration
-e^-y = (x^2 / 2) + C
y= ln ( x^2 / 2 + C )

0 = ln( 1 / 2 + C)
Thats where i get stuck I don't know quite how to solve for C.
Thats if i did all the previous steps correct. Any Help is Appreciated!
 
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