different base logarithms: log2 6 (log6 4)

Red

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Sep 30, 2006
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log2 6 (log6 4) I know to use the properties and change of base formula but i'm not sure the correct steps.
 
Re: different base logarithms

Red said:
log2 6 (log6 4) I know to use the properties and change of base formula but i'm not sure the correct steps.

I assume you are trying to multiply the two logs ?

\(\displaystyle \L (\log_2{6}) (\log_6{4}) =\)

\(\displaystyle \L (\log_2{6}) \frac{\log_2{4}}{\log_2{6}} =\)

\(\displaystyle \L \log_2{4} = 2\)
 
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