difference of squares

redhead13

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Oct 6, 2009
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how do i factor 25x^4/36 - 9y^8/16 using difference of squares?

Also how do I factor x^20-y^20 using difference of suares?

Thank you!
 
redhead13 said:
how do i factor 25x^4/36 - 9y^8/16 using difference of squares?

Also how do I factor x^20-y^20 using difference of suares?

Thank you!

It might help to realize that 25x[sup:3e45j4gk]4[/sup:3e45j4gk]/36 is the square of 5x[sup:3e45j4gk]2[/sup:3e45j4gk]/6, and 9y[sup:3e45j4gk]8[/sup:3e45j4gk]/16 is the square of 3y[sup:3e45j4gk]4[/sup:3e45j4gk]/4.

Then apply the pattern for factoring a difference of two squares.

For the second problem, x[sup:3e45j4gk]20[/sup:3e45j4gk] is (x[sup:3e45j4gk]10[/sup:3e45j4gk])[sup:3e45j4gk]2[/sup:3e45j4gk].......y[sup:3e45j4gk]20[/sup:3e45j4gk] is (y[sup:3e45j4gk]10[/sup:3e45j4gk])[sup:3e45j4gk]2[/sup:3e45j4gk]

Apply the pattern for a difference of two squares. Be sure to see if either of the factors you get can be factored further.
 
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