F(x)=x^2 [f(2+h)-f(2)]/h [f(z+h)-f(z)]/h
T twins12 New member Joined Feb 12, 2010 Messages 9 Mar 1, 2010 #1 F(x)=x^2 [f(2+h)-f(2)]/h [f(z+h)-f(z)]/h
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,128 Mar 1, 2010 #2 twins12 said: F(x)=x^2 [f(2+h)-f(2)]/h [f(z+h)-f(z)]/h Click to expand... I'm a bit confused...F(x) and f(x) are surely not the same thing. Please clarify what function you are supposed to use for f(2 + h) and f(2)....F(x) would not apply.
twins12 said: F(x)=x^2 [f(2+h)-f(2)]/h [f(z+h)-f(z)]/h Click to expand... I'm a bit confused...F(x) and f(x) are surely not the same thing. Please clarify what function you are supposed to use for f(2 + h) and f(2)....F(x) would not apply.
