Diffeentials

[nikchic5]

Hello. I really need help with this before my test tomorrow. If anyone could please help me!

I need to find the differentials dy and then evaluate dy for the given values of x and dx.

y= [the square root of 4+5x] x=o and dx=0.04

Thank you very much to anyone who can help me!!!

 

[daon]

\(\displaystyle y= \sqrt{4+5x}\)

\(\displaystyle dy= \frac{1}{2\sqrt{4+5x}}5dx\)

at the given values of x=0 and dx=0.04:

\(\displaystyle dy= \frac{1}{2\sqrt{4+5(0)}}5(0.04) = ?\)

 

[nikchic5]

Just Double Checking...

So the answer is 0.5 is that all you have to do?
Thank you very much...

 

[daon]

Yes but your answer is a little off.

 

[nikchic5]

Here it is..

Sorry I typed it in wrong. It is 0.05. Thanks!