Diff. f(x) = csc(x), p(x) = sin^5(x); find lim,x->0, of 1/x;

happyman

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Sep 18, 2008
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please help me:

1) differentiate: f(x)= csc(x)

2) differentiate: p(x) = (sin(x))^5

3) find lim as x approaches 0 of 1/x

4) if f(x) = 2x+6 then what is the inverse of f(x) =

I would really appreciate it if someone could show me how to solve these problemsand provide the answers
 
Re: various problems

happyman said:
please help me:

differentiate: f(x)= csc(x).......... change to sin(x) and apply rule of power in differentiation along with chain rule
differentiate: p(x) = (sin(x))^5 ....Use rule of power and chain rule of differentiation

find lim as x approaches 0 of 1/x

if f(x) = 2x+6 then what is the inverse of f(x) =

If you are having trouble with the above two problems - you really need to review pre-calc (where inverse functions are generally taught) and begining of limits.

I would really appreciate it if someone could show me how to solve these problemsand provide the answers
 
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