Wind, it seems to me that you have a mistaken idea about ‘wait-times and expectation’. This is a rather well know problem in negative binomial distributions. The expected number of tosses is given by
\(\displaystyle \L 6\left( {1 + \frac{1}{2} + \frac{1}{3} + \cdots + \frac{1}{6}} \right) \approx 14.7\). If you have a good mathematics library see the collector’s problem in PROBABILITY by Jim Pitman.
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