Determining the matrix for a transformation

Tgl

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Sep 2, 2020
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A transformation maps the complex number z = x + yi onto z’ such that z’ = (1-I)z.

How does one determine the matrix of this transformation?
 
A transformation maps the complex number z = x + yi onto z’ such that z’ = (1-I)z.
How does one determine the matrix of this transformation?
Please review what you posted: z=(1l)zz'={\large(1-l})z.
Did you not mean z=(1i)z ?\large z'=(1-i)z~?
 
To TQL; you did not answer, so we assume the mapping is f(a+bi)=(a+bi)(1i)=(a+b)+i(ba)f(a+bi)=(a+bi)(1-i)=(a+b)+i(b-a)
Here z=a+biz=a+bi where (z)=a & (z)=b\Re(z)=a~\&~\Im(z)=b using a two dimensional complex space we get:
\(f\left[ {\begin{array}{*{20}{c}}
a \\
b
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
1&{ 1} \\
{ - 1}&1
\end{array}} \right]\left[ {\begin{array}{*{20}{c}}
a \\
b
\end{array}} \right]\)\( = \left[ {\begin{array}{*{20}{c}}
{a + b} \\
{b - a}
\end{array}} \right]\)
 
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