Determine the limit of the trigonometric funcion if it exist

I'm going to guess that the limit is as follows:

. . . . .lim [(1 - cos<sup>2</sup>(h)) / h] / [h - 0]

If this is in error, please include clarification when you reply telling us the value that the variable is approaching. Thank you.

Eliz.
 
So the "2" isn't squaring? It's just multiplied on the "1 - cos(h)"? That does simplify things a lot: Check in your book, in the section that introduced trig derivatives. You'll find a limit for [cos(x) - 1]/x as x goes to zero. Use that to find this limit.

Eliz.
 
I suspect that it is [1−cos(h)]<SUP>2</SUP>/h .
 
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