Determinant of an nxn Matrix

ChaoticLlama

Junior Member
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Dec 11, 2004
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I don't want the full solution for this question, a first step or two would be all. I'm not sure how to approach the problem (ie: how should I go about row-reducing to make calculating the determinant easier?):

What is the determinant of an nxn matrix with a main-diagonal of lambdas and r's everywhere else.

\(\displaystyle \L\left| {\matrix{
\lambda & r & r & r & \cdots & r \cr
r & \lambda & r & r & \cdots & r \cr
r & r & \lambda & r & \cdots & r \cr
\vdots & {} & \ddots & \ddots & \ddots & \vdots \cr
\vdots & {} & {} & \ddots & \ddots & r \cr
r & \cdots & \cdots & \cdots & r & \lambda \cr

} } \right|\)

For interest, the answer is \(\displaystyle \L\
[\lambda + (n - 1)r](\lambda - r)^{n - 1}\)
 
You can try to do this by induction.
Start with a 2x2.
 
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