Will someone check my answers?
find the derivative.
f(x) = 4x^-3, find f(3)
My answer is f'(3) = -972
f(x) = 4 - 6 + 8
-- --- --- Find f(x)
x^1/2 x x^4
my answer is f'(x) = -2x^-3/2 + 6x^-2 - 32^-5
Find the slope of the line tangent to the graph of the function at the given value of x.
y= -8x^-1 + 5x^-2; x=2
My answer is y' = -48
Use product rule to find the derivative
f(x) = (3x-4) (x^1/2 +5)
My answer is 3/2x^1/2 - 2x^-1/2 +3/2x + 15
Use quotient rule to find derivative
y= x^2 + 8x + 3
-----------------
x^1/2
My answer 2x^7/2 + 12x^1/2 - 1/2x^3/2 + 3/2x^-1/2
Thanks
find the derivative.
f(x) = 4x^-3, find f(3)
My answer is f'(3) = -972
f(x) = 4 - 6 + 8
-- --- --- Find f(x)
x^1/2 x x^4
my answer is f'(x) = -2x^-3/2 + 6x^-2 - 32^-5
Find the slope of the line tangent to the graph of the function at the given value of x.
y= -8x^-1 + 5x^-2; x=2
My answer is y' = -48
Use product rule to find the derivative
f(x) = (3x-4) (x^1/2 +5)
My answer is 3/2x^1/2 - 2x^-1/2 +3/2x + 15
Use quotient rule to find derivative
y= x^2 + 8x + 3
-----------------
x^1/2
My answer 2x^7/2 + 12x^1/2 - 1/2x^3/2 + 3/2x^-1/2
Thanks