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derive multi vars
- Thread starter amnross
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D
Deleted member 4993
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Derive Eq. 7-1 for the average specific gravity.
spec grav avg=(((a*b)(1+r)) / ((r*b)+a))
How in the world do I derive for mult. var. like this one?
What is that - where is that???
re:
Derive Eq. 7-1 for the average specific gravity.
Eq. 7-1: spec grav avg=(((a*b)(1+r)) / ((r*b)+a))
How in the world do I derive for mult. var. like this one?
What is that - where is that???
Derive Eq. 7-1 for the average specific gravity.
Eq. 7-1: spec grav avg=(((a*b)(1+r)) / ((r*b)+a))
How in the world do I derive for mult. var. like this one?
D
Deleted member 4993
Guest
Derive Eq. 7-1 for the average specific gravity.
Eq. 7-1: spec grav avg=(((a*b)(1+r)) / ((r*b)+a))
How in the world do I derive for mult. var. like this one?
What are a, b and r?
Please post compplete problem including definitions of variables.
The question out of the book is "Derive Eq. 7-1 for the average specific gravity.
Eq. 7-1: Specific Gravity average=((spec. grav. of oxidizer*spec. grav. of fuel)(1+r))/((r*spec grav of fuel)+spec grav of oxidizer)
r=mixture ratio
Eq. 7-1: Specific Gravity average=((spec. grav. of oxidizer*spec. grav. of fuel)(1+r))/((r*spec grav of fuel)+spec grav of oxidizer)
r=mixture ratio
What are a, b and r?
Please post compplete problem including definitions of variables.
D
Deleted member 4993
Guest
The question out of the book is "Derive Eq. 7-1 for the average specific gravity.
Eq. 7-1: Specific Gravity average=((spec. grav. of oxidizer*spec. grav. of fuel)(1+r))/((r*spec grav of fuel)+spec grav of oxidizer)
r=mixture ratio
r=mixture ratio → is the mixture ratio by weight or by volume?
r=mixture ratio (mass flow rate of oxidizer to mass flow rate of fuel
r=mixture ratio → is the mixture ratio by weight or by volume?
D
Deleted member 4993
Guest
r=mixture ratio (mass flow rate of oxidizer to mass flow rate of fuel
Specific Gravity average=((spec. grav. of oxidizer*spec. grav. of fuel)(1+r))/((r*spec grav of fuel)+spec grav of oxidizer)
spec grav avg=(((a*b)(1+r)) / ((r*b)+a))
Let there be
r gm of fuel → volume = r/a cc
1 gm of fuel → volume= 1/b cc
specific gravity of mixture = (weight of the mixture)/(volume of the mixture) = (1 + r)/(r/a + 1/b) = a*b*(1+r)/(r*b + a)
Cannot be simpler than that - basic definitions and algebra. What grade math (or physics) is this?