derivatives

taylor13 said:
What is the derivative of f(x)= -x+tanx?

What do you think?

If

\(\displaystyle f(x) \ = \ g(x) + h(x)\)

then,

\(\displaystyle \frac{df(x)}{dx} \ = \ \frac{dg(x)}{dx} + \frac{dh(x)}{dx}\)

Please show us your work, indicating exactly where you are stuck - so that we may know where to begin to help you.
 
the derivative of tanx=sec^2x and i think the derivative of -x=-1 but after that i am lost!
 
taylor13 said:
the derivative of tanx=sec^2x and i think the derivative of -x=-1 but after that i am lost!

Like I explained - add those up.

\(\displaystyle \frac{d}{dx}[-x \ + \ tan(x)] \ = \ -1 \ + \ sec^2(x)\)

You could further simplyfy it using:

\(\displaystyle sec^2(x) \ = \ 1 \ + \ tan^2(x)\)
 
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