Derivatives

[i_<3_science]

I'm not sure how to calculate the derivative of: 8³√x :if anyone can help me or show me how to calculate the derivatives of similar problems such as this it would be greatly appreciated. Thanks

It says in the back of the book that the answer is: 8/3³√x¹¹

I have never done one of these problems before and this is how i tried to approach it:
8³√x
dy/dx = 8 X 1/2 ^3 x^1/2 - 1
= 8/2^3 x^-1/2

Thats what i kinda thought at first but it is so wrong

I've looked through the worked examples in the book and there are no problems like this. This is the only problem out of this section of exercises that I am having trouble with.....its really disapointing because it broke me groove and its really annoying me that I can't work it out!

 

[i_<3_science]

bye then

 

[i_<3_science]

bye then

I figured it out now anyways....gee ain't I PROUD :wink:

 

[stapel]

bye then

There is not a chat room, and there is no paid staff waiting on-hand to provide instant replies. The tutors are volunteers who give of their time as they are able. Many of them work and sleep, and some of them may even spend time with their families on national holidays. I apologize for any confusion.

Meanwhile, what was the actual function? Was it "8³ sqrt[x]"? Or "8 cbrt[x]"? Or something else? What rule or method were you using in your solution?

Thank you.

Eliz.

 

[i_<3_science]

sorry if i seemed inconsiderate....i didn't want that.

I used the cubed root of x.

 

[galactus]

I assume this is what you want to differentiate: \(\displaystyle \L\\ y\, =\, 8\, \sqrt[3]{x}\)

That is \(\displaystyle \L\\y\, =\, 8\, x^{\frac{1}{3}}\)


\(\displaystyle \L\\y'\, =\, \frac{8}{3}\, x^{\frac{-2}{3}}\, =\, \frac{8}{2x^{\frac{2}{3}}}\)

Is that what you got?. See how I arrived at that?.