Derivatives

[InterserveVB]

Anyone have any idea how to do this?

FInd a third-degree polynomial Q such that Q(1) = 3, Q(1)' = 8, Q(1)'' = 14, and Q'''(1) = 18

 

[Unco]

Hi,

A third degree polynomial looks something like this
Q(x) = ax^3 + bx^2 + cx + d

We know Q(1)=3. That is,
Q(1) = a + b + c + d = 3 (substituting x=1)

Now, differentiate once, twice, and thrice and do the same. You will find that you have triangular set of four equations, which is straightfoward to solve for a, b, c and d.

 

[InterserveVB]

Thx

Thank You. It worked out perfectly.