h(y)=(1+e^y)/(1-e^y) find h'(y)
S ssabadnama3 New member Joined May 3, 2009 Messages 7 May 3, 2009 #1 h(y)=(1+e^y)/(1-e^y) find h'(y)
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 May 3, 2009 #2 Re: derivatives Rewrite as 1+ey1−ey=−2ey−1−1\displaystyle \frac{1+e^{y}}{1-e^{y}}=\frac{-2}{e^{y}-1}-11−ey1+ey=ey−1−2−1 That should make it a little easier. Apply the quotient rule.
Re: derivatives Rewrite as 1+ey1−ey=−2ey−1−1\displaystyle \frac{1+e^{y}}{1-e^{y}}=\frac{-2}{e^{y}-1}-11−ey1+ey=ey−1−2−1 That should make it a little easier. Apply the quotient rule.
